If I'm not wrong, then it's not possible to make zero by adding 5 to a number squared and if it is not (-x)^2 +5 = 0, then how can you evaluate the value?
Your answer would be 3.4
Anything under 5 it stays the same and anything over 5 it goes up one
Answer:
11 coins for $1.99
Step-by-step explanation:
The maximum total less than $2 is $1.99. It takes 11 coins to make that total. It would take 1 fewer if the nickel were not required.
Starting with the minimum required coins, which total $0.91, we need to add $1.08 using a minimum number of coins. To minimize the added coins, we start with the largest we can use without going over the total: 2×50¢ + 1×5¢ + 3×1¢. These 6 coins added to the required 5 coins give the desired total using 11 coins.
11 coins: $1.99 . . . . (3×50¢ +1×25¢ +1×10¢ +2×5¢ +4×1¢)
$1.99 is the highest possible total less than $2.00, and it takes a minimum of 11 coins to make that total.
Answer:
The statement is true
Step-by-step explanation:
Positive numbers are always greater than negative numbers, so the statement would be true
Answer:
s2 = 19 a=19 u1= 19√2 (26.87) u2= 19√2 (26.87)
Step-by-step explanation:
s2 - subtrace s1 from h to get 19
a - use the geometric mean of s1 and s2 (squre root of 19 times 19)
u1 and u2 - pythagorean thm
