59×2=118 cost of bill.
59÷4=14.75 for the other 4 if the bill was 118 assuming Thomas pays half.
or...59 ×5=295
assuming they all pd 1/5 of the bill
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

Here the value of 3 is =3/10
Then 100 fold of 3/10=3/10*100=30
So, the number 26538,532,97436 etc. has that property.
Answer:

Step-by-step explanation:

What do you want to solve for? Substitute in c to find F. To solve for C,
<span>F - 32 = 9/5(c) </span>
<span>C = 5/9(F - 32)</span>