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photoshop1234 [79]
3 years ago
7

I will mark you as Brainliest.

Mathematics
1 answer:
beks73 [17]3 years ago
8 0

Answer:

We can't solve this because we can't add graphs. One way you could solve it would using Desmos.

Step-by-step explanation:

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1

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8 0
3 years ago
Two pools are being filled with water. To start, the first pool had 1850 liters of water and the second pool had 1334 liters of
prohojiy [21]

Answer:

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

Step-by-step explanation:

First Pool :

Initial amount of water in Pool = 1850 liters

Water is being added to the first pool at a rate of 27 liters per minute.

Amount of water added after x minutes = 27x

So, Total amount of water after x minutes = 1850+27x

Second Pool:

Initial amount of water in Pool = 1334 liters

Water is being added to the first pool at a rate of 39 liters per minute.

Amount of water added after x minutes = 39x

So, Total amount of water after x minutes = 1334+39x

Now to find  an equation to show when the two pools would have the same amount of water.

1850+27x= 1334+39x

1850-1334=39x-27x

516=12x

\frac{516}{12}=x

43 =x

Hence

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

5 0
3 years ago
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