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serious [3.7K]
3 years ago
11

Complete the sequence, 13, 14, 27, 41,​

Mathematics
1 answer:
olasank [31]3 years ago
5 0

Answer:

68

Step-by-step explanation:

We can see that the nth term would be the sum of the previous two terms. Continuing this would result in 68.

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The weight of two bags is 24/15kg . If the weight of one bag is 10/15. What will be the weight of other bag?
lys-0071 [83]
Weight of other bag would be 14/15 kg
5 0
3 years ago
savannah is painting a striped background for a mural on a wall that is 15 yards long. she wants a total of 96 stripes that’s ar
adell [148]
In this item, we are tasked to determine the calculation that can be done in order to determine the length or width of the painted mural in each striped area. This can be done by dividing the total length by the number of stripes as shown in the equation below.

   Length per stripe = Total length / number of stripes
    Length per stripe = 15 yards / 96 stripes
                           = 0.15625 yard/stripe
8 0
3 years ago
Read 2 more answers
Use properties to compare expression 5 x ( 6 x 3 )and ( 5 x 6) x 3
nadya68 [22]
5(6*3) = 5(18) = 90

(5*6)3 = (30)3 = 90

The answer is the same by the associative law.
6 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
How much is a square foot if the room is 15ft x 28ft?
Scrat [10]

Answer:

1 foot squared

Step-by-step explanation:

Er... a square foot is 1 foot squared

4 0
2 years ago
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