1) x1= -8 , x2=16
2) x= 11
3) 7/8 or 0.875
<h3>Hey there! </h3><h3>"The sum of twelve times p and d" </h3><h3>Firstly, you could pull out your key terms for better understanding of the expression</h3><h3>Here's your key terms </h3>
- Sum
- (Of) twelve
- Times
- P and D
<h3>Let's find out what each term mean for setting up your problem , easier </h3>


&
&
(since they are <em><u>unknown numbers</u></em>)
SO, this means that your answer SHOULD look like this:

Good luck on your assignment and enjoy your day!
~
9514 1404 393
Answer:
3.88%
Step-by-step explanation:
The probability that 1 is defective and 3 are not (out of four) is ...
P(1 of 4) = 4(0.01)(0.99)^3 ≈ 0.0388 = 3.88%
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The multiplier of 4 comes from the number of ways that 1 can be chosen from 4.