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3 years ago

The problem 1/3+1 5/6=

Mathematics

2 answers:

Tomtit [17]3 years ago

5 0

The answer is 2.6 or 2 1/6 or 13/6

soldi70 [24.7K]3 years ago

4 0

Mixed number form:2 1/6 Decimal form:2.16 exact form: 13/6

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can someone tell me how to work out this problems and ones similar to it? Jack has $16 in a savings account. The interest rate i

Ray Of Light [21]

It is a Simple interest problem .

principle = $16

rate = 5%

time = 1 year

simple interest = PRT/100

= (16 x 5 x 1)/100

= 4/5

= $0.80

amount after 1 year = 16 + 0.80 = $16.80

7 0

3 years ago

ANSWER FAST PLZ 20POINTS!!!!!!!!!!!!!!!!!!

Marianna [84]

Answer: 272 square feet

Step-by-step explanation:

We must find the total area of the backyard then subtract the area of the not allowed area from it. Clearly, the length and width of the backyard is 22 and 17ft respectively, so the total area is 22*17=374ft^2.

The restricted space can be seen as two rectangles, both with width 3 and length 17, making their area 2(17*3) =102

374-102= 272

6 0

4 years ago

Can y’all please help me answer these questions

mario62 [17]

Step-by-step explanation:

⇒ $V = \pi r^{2}h$

⇒ $V = \pi(10)^{2}(40)$

⇒ $V = 4000\pi$

⇒ $V = 12566.4cm^{3}$

⇒ $V = \frac{1}{3}\pi r^{2}h$

⇒ $V = \frac{1}{3}\pi (8)^{2}(h)$

As we know the radius and slant height, we can use Pythagoras' Theorem to find the perpendicular height.

⇒ $a^{2} + b^{2} = c^{2}$

⇒ $(8)^{2} + h^{2} = 20^{2}$

⇒ $h = \sqrt{20^{2} - 8^{2}}$

⇒ $h = 4\sqrt{21}$

Now substitute this into the volume formula.

⇒ $V = \frac{1}{3}\pi (8)^{2}(4\sqrt{21})$

⇒ $V = \frac{256\sqrt{21} }{3}\pi$

⇒ $V = 1228.5mm^{3}$

⇒ $V = l^{3}$

⇒ $V = (3.1)^{3}$

⇒ $V = 29.8inches^{3}$

⇒ $V = \frac{1}{3}lwh$

⇒ $V = \frac{1}{3}(12)(4)(6)$

⇒ $V = 96inches^{3}$

6 0

3 years ago

Read 2 more answers

Find a function for the graph below.

sammy [17]

Answer:

Step-by-step explanation:

From the graph you can see that y changes from -2 to 2, so the range of the function is $[-2,2].$

Since the range of the functions $y=\cos x$ and $y=\sin x$ is $[-1,1]$ and the range of the functions $y=k\cos x$ and $y=k\sin x$ is $[-k,k],$ we can state that the correct option is C: $f(t)=-2\cos 3t.$