Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Answer
$540
Step-by-step explanation:
hopes this helps
Answer:
2.016
Step-by-step explanation:
In your equasion, I couldn't tell if you need to multipy 0.8^2 by 3.15 or are you asking something else? If you want to multiply, the answer is 2.016.
Let's look at it like this:
5/10+1/5 = (5/10) + (1/5)
5/10 = 0,5
1/5 = 0,2
so it's 5/10 + 1/5 = (5/10) + (1/5) = 0,5 + 0,2 = <u>0,7 </u>
Answer: its −2
Step-by-step explanation:
3*(5*x+2)-(2*(3*x-6))=0
Step by step solution :
STEP
1
:
STEP
2
:
Pulling out like terms
2.1 Pull out like factors :
3x - 6 = 3 • (x - 2)
Equation at the end of step
2
:
(3 • (5x + 2)) - 6 • (x - 2) = 0
STEP
3
:
Equation at the end of step 3
3 • (5x + 2) - 6 • (x - 2) = 0
STEP
4
:
STEP
5
:
Pulling out like terms
5.1 Pull out like factors :
9x + 18 = 9 • (x + 2)
Equation at the end of step
5
:
9 • (x + 2) = 0
STEP
6
:
Equations which are never true
6.1 Solve : 9 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
6.2 Solve : x+2 = 0
Subtract 2 from both sides of the equation :
x = -2
One solution was found :
x = -2
