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anyanavicka [17]
2 years ago
8

Find side x , give your answer 1 decimal place ​

Mathematics
1 answer:
Vladimir [108]2 years ago
4 0

<u>Given</u>:

Let A denote the angle of the given triangle which measures ∠A = 81°

Let B denote the angle which measures ∠B = 40°

The length of the side a = x.

The length of the side b = 7 cm.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the law of sine formula.

Applying the law of sine, we have;

\frac{sin \ A}{a}=\frac{sin \ B}{b}

Substituting the values, we have;

\frac{sin \ 81^{\circ}}{x}=\frac{sin \ 40^{\circ}}{7}

Simplifying, we get;

\frac{0.988}{x}=\frac{0.643}{7}

Cross multiplying, we have;

0.988 \times 7=0.643 x

     6.916=0.643x

       10.8=x

Thus, the length of the side x is 10.8 cm.

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Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

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\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

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