12 I think bro but trust your gut good luck
Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:
0.70275
Step-by-step explanation:
Data provided in the question:
4e²ˣ⁻¹ -1 = 5
now solving for 'x'
⇒ 4e²ˣ⁻¹ = 5 + 1
or
⇒ 4e²ˣ⁻¹ = 6
or
⇒ 
or
⇒ 
now,
taking natural log both sides, we get
⇒ 2x - 1 = 
also,
we know
⇒
thus,
⇒ 2x - 1 = ln(3) - ln(2)
or
⇒ 2x - 1 = 1.0986 - 0.6931
or
⇒ 2x - 1 = 0.4055
or
⇒ 2x = 0.4055 + 1
or
⇒ 2x = 1.4055
or
⇒ x = 0.70275
Yes, as one half or 1/2 is also 10/20. 11/20 is greater than half by a 10% margin.