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jolli1 [7]
3 years ago
14

What’s the answers?...

Mathematics
1 answer:
zmey [24]3 years ago
4 0

Answer:

x=10

z=2

y=5

Step-by-step explanation:

We know the triangles are congruent, therefore, each corresponding side of the triangle is also congruent!

1) Set EF≅CB

x+15=2x+5

x+10=2x

x=10

2) Set ED≅CA

10z-5=3z+9

10z=3z+14

7z=14

z=2

3) Set DF≅AB

4y=8y-20

-4y=-20

y=5

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A. 2y − 17y R 70<br> B. 2y − 17y R −70<br> C. 2y − 3<br> D. 2y + 3
11111nata11111 [884]
D.2y+3 i think is the answer

6 0
3 years ago
Use the remainder theorem to find the remainder of 2x^4 + x^2 - 10x -1 divided by x +2.
I am Lyosha [343]

Answer:

The remainder is 55

Step-by-step explanation:

Let

p(x)= 2 {x}^{4}  +  {x}^{2}  - 10x - 1

According to the remainder theorem, if p(x) is divided by x+a, the remainder is p (-a).

The given divisor is x+2, therefore the remainder is given by:

p( - 2)

We substitute x=-2 to get:

p( - 2)= 2 {( - 2)}^{4}  +  {( - 2)}^{2}  - 10( - 2) - 1

We simplify to obtain:

p( - 2)= 2  \times 16 +  4  +  20- 1

We multiply to get:

p( - 2)=3 2  +  4  +  20- 1 = 55

Therefore the remainder is 55

4 0
3 years ago
What is the range of the function in this table?
kodGreya [7K]

Answer:

C. {1, 2, 4}

Step-by-step explanation:

In a function, the range are the values of the outputs. They are also the y-values. In a table, the range would be on the right side on the table.

According to the table, the numbers under the 'y' column are 1, 4, 4, and 2. Therefore, the range is: {1, 2, 4}.

Option C should the correct answer.

6 0
3 years ago
Math solve questions<br><img src="https://tex.z-dn.net/?f=9%20-%20%20%5Csqrt%7By%20-%204%20%3D%205%7D%20" id="TexFormula1" title
Whitepunk [10]

Answer:

y = 20

Step-by-step explanation:

9 -  \sqrt{y - 4}  = 5

<h3>i) move 9 to the right-hand side and change its sign</h3>

-  \sqrt{y - 4}  = 5 - 9

<h3>ii) calculate the difference</h3>

-  \sqrt{  y - 4}  =  - 4

<h3>iii) change the signs on both sides of the equation</h3>

\sqrt{y - 4}  = 4

<h3>iv) square both sides of the equation</h3>

( \sqrt{y - 4} ) {}^{2}  = 4 {}^{2}

y - 4 = 4 {}^{2}

y - 4 = 16

<h3>v) move -4 to the right-hand side and change its sign</h3>

y = 16 + 4

<h3>vi) add the numbers</h3>

y = 20

6 0
3 years ago
Read 2 more answers
Please help if u cannot skip
posledela

The statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

<h3>How to determine which statement is true?</h3>

To determine which statement is true, we need to know the conditions for continuity and differentiablity of a function.

<h3>Conditions for continuity and differentiablity of a function.</h3>
  • For a function f(x) to be continuous at a point x = a, then both the left hand limit of f(x) and the right hand limit of f(x) as x → a must be equal. That is \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x). So,  \lim_{x \to a^{} } f(x) must exist since  \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x) =  \lim_{x \to a^{} } f(x)
  • Also, for a function to be differentiable at a point x = a, it must also exist at x = a

So, since f(x) = {x² - 1 if -1 ≤ x ≤ 3 and x²/3 if 3 < x ≤ 8}

From the equality on the first condition,we see that f(x) is exists at x = 3 but is not continuous since f(x) changes to another function when x > 3. So,left hand limit of f(x) and the right hand limit of f(x) as x → 3 are not equal.

That is \lim_{x \to 3^{-} } f(x) \neq   \lim_{x \to 3^{+} } f(x) . Thus, the function is discontinuous at x = 3.

For differentiability, both conditions must be met. Since only one condition is met, it is non-differentiable.

So, the function is discontinuous and non-differentiable at x = 3.

So, the statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

Learn more about continuity of a function here:

brainly.com/question/24177259

#SPJ1

4 0
2 years ago
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