Question

A projectile is launched from ground level with an initial velocity of 89 ft/sec. It's height(ft), t seconds after launching is given by s=-16t^2 + v0t + s0. a) Fine the time(s) the projectile will reach a height of 100 feet. b) find the time it takes the projectile to hit the ground

Answer 1

Answer:

Step-by-step explanation:

Initial Velocity of projection = 89ft/sec

height(ft), t seconds after launching is given by s=-16t^2 + v0t + s0

A) time the projectile will reach a height of 100 ft

s=-16t^2 + v0t

v0 = 89ft/sec

s = 100ft

100 = - 16t² + 89t

-16t² + 89t - 100 = 0

Using the online quadratic equation solver;

t = 4s or t = 1.5625