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3 years ago

PLEASE HELP ASAP!!!!

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

3 0

Answer:

D. $y=\frac{1}{4}x$

Step-by-step explanation:

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Mr. Drew wants to build a square sandbox with an area of 361 square feet. What is the total length of the wood Mr. Drew needs ma

Zepler [3.9K]

Answer:

The Sandbox must be 19x19 for the area to be 361.

Step-by-step explanation:

(19x19=361)

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4 years ago

Plz answer this question

Korvikt [17]

Answer:

-12b+6c+18

Step-by-step explanation:

you just need to add the same numbers and stuff

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2 years ago

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Simplify<br> (3y)^2 x y^-1

konstantin123 [22]

Answer:

Step-by-step explanation:

$\bullet\; \tt{(3y)^2} = 3^2y^2 = 9y^2}$

$\bullet\; \tt y^{-1} = \dfrac{1}{y}\\\\\bullet\;(3y)^2 \times y^{-1} = 9y^2 \times \dfrac{1}{y } = \dfrac{9y^2}{y}\\\\\\bullet \tt \dfrac{y^2}{y} = y\\\\\tt \bullet \dfrac{9y^2}{y} = 9y$

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1 year ago

Help me please please pleade help me!!

emmasim [6.3K]

Answer:

ang hirap pre sobramg hirap

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3 years ago

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An exam consists of two parts, Section X and Section Y. There can be a maximum of 95 questions. There must be at least 20 more q

GuDViN [60]

Answer:

X + Y <= 95.

Y >= 20+ X.

Step-by-step explanation:

It is given that section X and section Y can have hardly 95 questions.

Hence either both have them has total 95 questions or less than 95 questions.

If we take X as the number of questions section X has and Y as the number of questions section Y has then X + Y <= 95.

Also it is given that Y has at least more 20 more questions than Y has. Hence Y can have 20 more question than X has or more than 20 more question than X.

That is Y >= 20+ X.

As shown in the graph the line passing through (95, 0) and (0, 95) the arrows are towards the origin because the origin satisfies the equation.

In the other line the origin that is (0, 0) does not satisfy the equation. Hence the arrows will not be towards the origin.

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3 years ago