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2 years ago

Factor each. 5x to the 3rd ppwer + 25x to the 2nd power -4x -20 = 0

Mathematics

1 answer:

lesya692 [45]2 years ago

4 0

If you are looking forward to adding them together you will get 145. Just need to know if this questions had options?

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Lyrx [107]

Answer:

x = -5

y = 20

Step-by-step explanation:

3x + y = 5

3x - 3x + y = 5 - 3x

y = 5 - 3x

--------------------------------------------------------

4x + 2y = 20

4x + 2(5 - 3x) = 20

4x + 2(5) + 2(-3x) = 20

4x + 10 - 6x = 20

10 - 2x = 20

10 - 10 - 2x = 20 - 10

-2x = 10

-2x ÷ -2 = 10 ÷ -2

x = -5

--------------------------------------------------------

y = 5 - 3x

y = 5 - 3(-5)

y = 5 + 15

y = 20

5 0

3 years ago

The point U(5, -5) is translated 10 units left.<br> U'?

Dahasolnce [82]

Answer:

(-5, -5)

Step-by-step explanation:

(5, -5)

Subtract the x axis minus 10

5 - 10 = -5

So that would mean the point U' is (-5, -5)

On A graph it would look the same as well

Hope this helps :)

8 0

2 years ago

Read 2 more answers

Find the 81st term of the arithmetic sequence 24, 11, -2, ...24,11,−2

FromTheMoon [43]

Answer:

The 81st term of arithmetic sequence is -1016

Step-by-step explanation:

Formula for arithmetic sequence is given by,

$a_n=a_1+\left(n-1\right)d$

Where,

$a_n=n^{th} \:term\:of\:sequence=a_81$

Therefore value of n is n = 81.

$a_1=1^{st} \:term\:of\:sequence=24$

$d=common\:difference$

Common difference is calculated by subtracting second term from first term as follows,

$d=a_{n+1}-a_{n}$

Therefore for first two terms that is 24 and 11 common difference is,

$d=11-24=-13$

Therefore for next two terms that is 11 and -2 common difference is,

$d=-2-11=-13$

Hence common difference is $d=-13$

Substituting the value,

$a_{81}=24+13\left(81-1\right)$

Simplifying,

$a_{81}=24+\left(-13\right)\left(81-1\right)$

$a_{81}=24+\left(-1040\right)$

$a_{81}=24-1040$

$a_{81}=-1016$

Therefore, the 81st term of the arithmetic sequence 24, 11, -2, ... is -1016

5 0

3 years ago

Which relation is a function? Group of answer choices (2, 7), (6, 5), (4, 4), (3, 3), (2, 1) (9, −3), (9, 3), (4, −2), (4, 2), (

leonid [27]

Given:

The relations in the options.

To find:

The relation which is a function.

Solution:

Consider the options are :

(a) {(2, 7), (6, 5), (4, 4), (3, 3), (2, 1)}

(b) {(9, −3), (9, 3), (4, −2), (4, 2), (0, 0)}

(d) {(1, 1), (2, 2), (3, 3), (4, 4), (5, 8)}

A relation is a function if there exist a unique y-value for each x-value.

In option (a), y=7 and y=1 at x=2. So, it is not a function.

In option (b), y=-3 and y=3 at x=9. So, it is not a function.

In option (c), y=0 and y=1 at x=3. So, it is not a function.

In option (d), there are unique y-value for each x-value. So, it is a function.

Therefore, the correct option is (d).

6 0

3 years ago

What is the length of leg y of the right triangle?

xz_007 [3.2K]

Answer:

Step-by-step explanation:

We need to use the Pythagorean Theorem to solve this problem:

$a^{2} +b^{2} = c^{2}$ , where a and b are the legs of the right triangle and c is the hypotenuse

In this case, we already know b (b = 84) and c (c = 85), so we need to solve for a:

$a^{2} = c^{2} - b^{2} = 85^{2} - 84^{2} = 169 = 13^{2}$

Thus, a = y = 13.

4 0

2 years ago

Read 2 more answers