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KATRIN_1 [288]
3 years ago
6

Computers from a certain manufacturer have a mean lifetime of 62 months, with a standard deviation of 12 months. The distributio

n of lifetimes is not assumed to be symmetric. Between what two lifetimes does Chebyshev's Theorem guarantee that we will find at least approximately 75% of the computers
Mathematics
1 answer:
Goryan [66]3 years ago
6 0

Answer:

Between 38 and 86 months.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of 62, standard deviation of 12.

Between what two lifetimes does Chebyshev's Theorem guarantee that we will find at least approximately 75% of the computers?

Within 2 standard deviations of the mean, so:

62 - 2*12 = 38

62 + 2*12 = 86

Between 38 and 86 months.

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Answer:

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x is -2 and 4 the midpoint is 1

y is 1 an 3 the midpoint is 2

(1,2)

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4x=4+4<br>Find the value of x​
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\sf\longmapsto \: x =2

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4 0
2 years ago
Read 2 more answers
PLEASSSSSE I NEED HELP BAD HELP PLEASE
charle [14.2K]

Answer:

See explanation

Step-by-step explanation:

Given the equation 3x-4y=12

A. Create the table of values for at least 4 points.

When x=0,

3\cdot 0-4y=12\\ \\-4y=12\\ \\y=-3

When x=2,

3\cdot 2-4y=12\\ \\-4y=12-6\\ \\-4y=6\\ \\y=-1.5

When x=4,

3\cdot 4-4y=12\\ \\-4y=12-12\\ \\-4y=0\\ \\y=0

When x=6,

3\cdot 6-4y=12\\ \\-4y=12-18\\ \\-4y=-6\\ \\y=1.5

When x=8,

3\cdot 8-4y=12\\ \\-4y=12-24\\ \\-4y=-12\\ \\y=3

Thus, the table is

\begin{array}{cc}x&y\\0&-3\\2&-1.5\\4&0\\6&1.5\\8&3\end{array}

B. Use the table of values to graph the line on the coordinate plane. Plot given points and connect them with the straight line (see attached diagram).

7 0
3 years ago
A jar holds no more than 500 buttons. If 5 people bring 330 buttons each, how many jars are necessary to hold all of the buttons
Strike441 [17]

Answer:

We know

1 jar = 500 buttons

5 people bring 330 buttons EACH

We can find/solve by...

people x buttons = total buttons

total buttons / 500 = number of jars needed

So..

5 x 330 = 1650

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Your answer:

4 jars

Explanation

It's impossible to have 3.3 jars, so you must round up.

Step-by-step explanation:

8 0
3 years ago
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