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goldfiish [28.3K]

3 years ago

10

Why are only some quadrilaterals parallelograms?

1 answer:

borishaifa [10]3 years ago

3 0

A parallelogram is a quadrilateral in which both pairs of opposite sides are parallel . ... Opposite sides are congruent; Adjacent angles are supplementary; The diagonals bisect each other.

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(WILL GIVE BRAINLIEST) Solve for x.

Oksanka [162]

Answer:

−2(−9x+5)−4x=2(x−5)−4

Step 1: Simplify both sides of the equation.

−2(−9x+5)−4x=2(x−5)−4

(−2)(−9x)+(−2)(5)+−4x=(2)(x)+(2)(−5)+−4(Distribute)

18x+−10+−4x=2x+−10+−4

(18x+−4x)+(−10)=(2x)+(−10+−4)(Combine Like Terms)

14x+−10=2x+−14

14x−10=2x−14

Step 2: Subtract 2x from both sides.

14x−10−2x=2x−14−2x

12x−10=−14

Step 3: Add 10 to both sides.

12x−10+10=−14+10

12x=−4

Step 4: Divide both sides by 12.

12x

12

=

−4

12

x= -1/3

Step-by-step explanation:

Good luck! Hope this helps! <3

3 0

2 years ago

Read 2 more answers

There are 2 trucks for every 3 cars in the parking lot. How

daser333 [38]

How many parking spaces are there?????

8 0

2 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation $A=45e^{-0.05t}$ .

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate $A=15$ and solve for t as:

$15=45e^{-0.05t}$

$\frac{15}{45}=\frac{45e^{-0.05t}}{45}$

$\frac{1}{3}=e^{-0.05t}$

Now we will switch sides:

$e^{-0.05t}=\frac{1}{3}$

Let us take natural log on both sides of equation.

$\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})$

$-0.05t\cdot (1)=\text{ln}(\frac{1}{3})$

$-0.05t=\text{ln}(\frac{1}{3})$

$t=\frac{\text{ln}(\frac{1}{3})}{-0.05}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}$

$t=-\text{ln}(\frac{1}{3})\cdot 20$

$t=-(\text{ln}(1)-\text{ln}(3))\cdot 20$

$t=-(0-\text{ln}(3))\cdot 20$

$t=20\text{ln}(3)$

Therefore, it will take $20\text{ln}(3)$ years for area of the glacier to decrease to 15 square kilo-meters.

6 0

2 years ago

The figure is made up of 2 rectangles and 2 right triangles.

Zarrin [17]

Answer:

area = 277 units²

Step-by-step explanation:

area = (25 x 5) + (8 x 13) + (8 x 6) = 277 units²

7 0

2 years ago

6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each

umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em /> $n = 35$ <em> --- the number of lines</em>

<em /> $d = 3$ <em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

<em>0 intersection for 1 line</em>
<em>1 intersection for 2 lines</em>
<em>3 intersections for 3 lines</em>
<em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

$n_k = \frac{n \times (n - 1)}{2}$

In this case, $n = 35.$

So, we have:

$n_k = \frac{35 \times (35 - 1)}{2}$

$n_k = \frac{35 \times 34}{2}$

$n_k = 35 \times 17$

$n_k = 595$

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0

2 years ago

Read 2 more answers