We want to find

, for

.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)

.
Answer: The answer is 0.18
Step-by-step explanation:
I took the test
The function is undefinded if the denominator, x-5, equals 0.
So

.
The domain is

.
In interval notation, this is (-infinity, 5) u (5, infinity).
Please write that as 4.321 × 10^(−4). The " ^ " indicates exponentiation and the parentheses help make clear that your exponent here is a negative one.
Rewrite 4.321 × 10^(−4) by moving the decimal point 4 places to the left:
0.0004321