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3 years ago

Create an example of a situation where there is a negative cash flow.

Mathematics

1 answer:

dimaraw [331]3 years ago

6 0

Answer:

when say your expenses are $400 a month but your income is only $350 a month that is -$50 every month so in that case you aren't getting a positive cash flow (which would be making more money than your expenses) So you must be getting a negative cash flow in which you are losing money and going into debt.

Hope this Helps :)

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The bakery shop purchased 7 2/10 pounds of sugar and 7 5/10 pounds of flour. How much sugar and flour did they purchase in all?

gizmo_the_mogwai [7]

Answer:

Sugar = 1-2/5 pounds, Flour = 3-1/2 pounds

Together = 5-9/10 pounds

Step-by-step explanation:

sugar = 7(2/10)

flour = 7(5/10)

sugar + flour = 7(2/10) + 7(5/10)

sugar = 14/10 or 1-2/5 pounds

flour = 35/10 or 3-1/2 pounds

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3 years ago

A tennis ball is in a cylindrical container. The ball has a radius of 5 inches and the cylinder has a height of 8 inches. How mu

Nostrana [21]

Answer:

104.7 in^3

Step-by-step explanation:

Step one:

given data

The ball has a radius of 5 inches and

the cylinder has a height of 8 inches

Step two:

The volume of the cylinder

$v= \pi r^2 h$

substitute our data

$v= 3.142*5^2*8\\\\v=628.4in^3$

The volume of the ball

$v=4/3 \pi r^3$

substitute our data

$v= 4/3 *3.142*5^3\\\\v= 523.7 in^3$

The space will have a volume of

=628.4-523.7

=104.7 in^3

7 0

3 years ago

When the end result is an untrue statement, how many solutions does the equation have?

Anit [1.1K]

Answer:

no solutions

Step-by-step explanation:

if the end result of solving an equation is untrue, it means there is no number that will satisfy the equation, therefore the equation will have no solutions

7 0

3 years ago

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If it takes 20 N to move a box, how much power will be needed to move the box a distance of 5 meters in 5 seconds?

Dmitry [639]

Power is work done per time and work done is force times distance. The power is found by multiplying the force(20N) and the distance(5m) and dividing the product by the time(5s)
(20*5)/5=20Nm/s OR 20 watts.
Therefore the power needed is 20 watts.

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4 years ago

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A survey said that 3 out of 5 students enrolled in higher education took at least one online course last fall. Explain your calc

marysya [2.9K]

Answer:

a) 60% probability that student took at least one online course

b) 40% probability that student did not take an online course

c) 12.96% probability that all 4 students selected took online courses.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they took at least one online course last fall, or they did not. The probability of a student taking an online course is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

3 out of 5 students enrolled in higher education took at least one online course last fall.

This means that $p = \frac{3}{5} = 0.6$

a) If you were to pick at random 1 student enrolled in higher education, what is the probability that student took at least one online course?

This is P(X = 1) when n = 1. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{1,1}.(0.6)^{1}.(0.4)^{0} = 0.6$

60% probability that student took at least one online course.

b) If you were to pick at random 1 student enrolled in higher education, what is the probability that student did not take an online course?

This is P(X = 0) when n = 1.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1,1}.(0.6)^{0}.(0.4)^{1} = 0.4$

40% probability that student did not take an online course

c) Now, consider the scenario that you are going to select random select 4 students enrolled in higher education. Find the probability that all 4 students selected took online courses

This is P(X = 4) when n = 4.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.6)^{4}.(0.4)^{0} = 0.1296$

12.96% probability that all 4 students selected took online courses.

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3 years ago