Question

The point A(-3, -2) is translated using T: (x,y) → (x + 5, y - 3). What is the distance from A to A'?

Answer 1

Answer:

d=5.39 units

Step-by-step explanation:

Given A (-3, -2)  

T= (x+5, y-3)

T= (-3+5, -2-3)

T=(2,-5)

Applying the translation on;

A( -3,-2)

A' (-3+2, -2+ -5)

A'= (-1, -7)

Distance

d= $\sqrt { X2-X1)^2 + (Y2-Y1)^2$

A = (-3,-2)     and  A'(-1, -7)

d=√ (-1--3)² + (-7--2)²

d=√ (2)²+(-5)²

d=√4+25

d=√29

d=5.39 units