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3 years ago

13

Help me pls. Pls do this step by step. I will give he brainliest to the person who does it step by step.

1 answer:

Zanzabum3 years ago

3 0

Answer:

x^2 - x^3 - 3x^2y - 3xy^2

Step-by-step explanation:

x^3 +y^3 - (x + y)^3

Expand the expression

x^2 + y^3 - (x^3 + 3x^2y + 3xy^2 +y3)

Remove the parentheses

x^2 +y^3 -x^3 -3x^2y -3xy^2 - y^3

Remove the opposites

Answer:

x^2 - x^3 - 3x^2y - 3xy^2

Hope this Helps!

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Please answer 25 points!

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Answer:

-3

Step-by-step explanation:

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3 years ago

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The ages in years of 21 people in a swimming pool are displayed in the stem-and-leaf plot. Determine the median age of

LenaWriter [7]

Answer:

<h3>5 years</h3>

Step-by-step explanation:

To get the median of the ages given

2, 4, 5, 6, 7, 8, 8, 8, 0, 3, 5, 9, 1, 4, 7, 6, 1, 2, 4, 4, 8

First we will need to rearrange the median ages in ascending order (from lowest to highest)

0, 1, 1, 2, 2, 3, 4, 4, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8, 8, 9

Next is to locate the middle value of the arranged data

(0, 1, 1, 2, 2, 3, 4, 4, 4, 4), 5, (5, 6, 6, 7, 7, 8, 8, 8, 8, 9)

The total values in both parenthesis are the same(10 in numbers) leaving 5 as the middle number.

Hence the median age of the people in the pool is 5years

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3 years ago

Mary wants to have$8500 to travel to south america when she is 21. She currently has $6439 in a savings account earning 4% annua

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Answer:

9,014.6

Step-by-step explanation:

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3 years ago

If you talk for 140 minutes, determine what would be the monthly cost using the equation and your

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We need more detail to help with the problem.

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago