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3 years ago

Indica si cada afirmación es verdadero (v) o falso (f) .

1 answer:

5 0

<span>A es falso porque podría dividirse por negativo.

B es verdadero porque el divisor siempre entrará en el dividendo.

C es falso porque cambiar el orden dará lugar a respuestas diferentes.

D es falso porque la propiedad asociativa no se aplica a la división.

E es falso porque no es "solo suficiente", aún necesita asegurarse de que el dividendo sea un número entero y el divisor sea un factor del dividendo.</span>

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HELP PLS IM DUM

Andrews [41]

ur not dum

Answer:

Paul

Step-by-step explanation:

Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.

Computing the return of both

Monica return is 100*3.4%= $3.4 in a year

Paul return is 200*%2.2= $4.4 in a year.

5 0

2 years ago

Help ASAP

polet [3.4K]

Answer:

a and c

Step-by-step explanation:

3 0

3 years ago

Can you guy's please help me out I was absent and now I don't have a clue!

Elena-2011 [213]

For these problems you have to use PEMDAS so for problem 15 you would do the parentheses first, (21-3) you get 18 and then exponents, 3^2, you get 9, no multiplication but there is division so take your answers, 18 and 9 and divide them, you get 2, so the answer to 15 is 2.

6 0

3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago

If a 171 mile trip took 9 1/2 gallin of gas how much gas is needed for a 247-mile trip?

masya89 [10]

<span>9.5 gallons 171 miles
_______________
9.5 gallons x miles
_______________
x = 171(9.5)/247 =
</span>

8 0

3 years ago