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3 years ago

I need help on this.

Mathematics

1 answer:

liraira [26]3 years ago

7 0

If the triangles are similar, the proportion of the legs on the left to the legs on the right will be equal. This proportion would look like:

$\frac{2x+1}{3x}=\frac{10}{14}$

(You needed to combine the orange segment and the yellow segment to find the total length of the large triangle).

Now, cross multiply and solve for x:

28x+14=30x

<em>*Subtract 28x from both sides to isolate the variable*</em>

14=2x

<em>*Divide both sides by 2*</em>

7=x

Hope this helps!!

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1/2 × 2 1/3 can u help

lawyer [7]

Thats easy its 7/6 hope this helps

7 0

3 years ago

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Which expression can be used to solve 3/5 divide by 7/10

kramer

Answer:

$\frac{3}{5} *\frac{10}{7}$

= $\frac{30}{35} =\frac{6}{7}$

7 0

3 years ago

After the drama club sold 100 tickets to a show, it had $300 in profit. After the next show, it had sold a total of 200 tickets

Alinara [238K]

Answer:

Option a : $y-300 = 4(x - 100)$

Step-by-step explanation:

Given :

The drama club sold 100 tickets to a show, it had $300 in profit.

The next show, it had sold a total of 200 tickets and had a total of $700 profit.

To Find : Equation models the total profit, y, based on the number of tickets sold, x

Solution :

For 100 tickets he had $300 in profit .

⇒ ( $x_{1} ,y_{1}$ )=(100,300)

For 200 tickets he had $700 in profit .

⇒ ( $x_{2} ,y_{2}$ )=(200,700)

We will use point slope form i.e.

$y-y_{1} = m(x - x_{1})$ --(A)

Now, to calculate m we will use slope formula :

$m = \frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

$m = \frac{700 -300}{200-100}$

$m =4$

Now, putting values in (A)

$y-300 = 4(x - 100)$

Thus Option a is correct i.e. $y-300 = 4(x - 100)$

5 0

3 years ago

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Solve the equation for W and L

Roman55 [17]

Answer:

Step-by-step explanation:

Cross multiply and get:

$\sqrt{7}$ L = 5w

L = 5w/ $\sqrt{7}$

W = $\sqrt{7}$ L/5

4 0

3 years ago

If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used: