Look at the attached files.
Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
Answer:
441 seats are being used :]
Step-by-step explanation:
Answer: The unit for Warren’s data is the number of cars sold each day.
Sorry for the answer being so late!
Answer:
1.SAS, ASA,
2. Not congruent
3.C
4. If you could screenshot the whole page I can give tell you what it is.
