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MAXImum [283]
2 years ago
9

Expand.Your answer should be a polynomial in standard form.(9h+3)(-h-1)​

Mathematics
2 answers:
djverab [1.8K]2 years ago
8 0

Answer:

Step-by-step explanation:

Elena-2011 [213]2 years ago
3 0
Just do foil or the box method to get the answer

You might be interested in
Write an equation for the nth term of the arithmetic sequence.
tresset_1 [31]

Answer:

<h3>              \bold{a_n=6n-3}\\\\\bold{a_{50}=297} </h3>

Step-by-step explanation:

3, 9, 15, 21,  ...

9-3 = 6;   15-9 = 6;   21-15 = 6   ⇒  d = 6

first term:  a = 3

difference:  d = 6

so the formula:

                         a_n=a+d(n-1)\\\\a_n=69+6(n-1)\\\\a_n =3+6n-6\\\\\underline{a_n=6n-3}                        

and:

   a_{50}=6\cdot50-3=300-3=297

5 0
2 years ago
a) work out the value of 4^3-5^2 b) work out the value of 6^2+3^3​
Dmitriy789 [7]

The answer of the given questions

a) 39 and b) 63

Step-by-step explanation:

Here are the solutions of given questions

a) 4^{3} -5^{2}

=64-25

=39

b) 6^{2} +3^{3}

= 36+27

= 63

5 0
2 years ago
Read 2 more answers
I need serious help grades go in tonighttt
attashe74 [19]
Rewrite it from least to greatest and set it up like shown

8 0
2 years ago
I need this answer asap
densk [106]

Answer:

16 x 6 divided by 2 is 48

First add the two bases together whenever you're trying to find the area of a trapezoid then multiply it by the height and multiply by it by 1/2 (which basically you divide by 2).

7 0
2 years ago
Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic
Free_Kalibri [48]

The equation for the situation is y=200(\frac{2}{3})^{x}

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is \frac{2}{3}

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is y=a(b)^{x} , where y represent the

   population in x years

∵ a = 200

∵ b = \frac{2}{3}

∴ y=200(\frac{2}{3})^{x}

The equation for the situation is y=200(\frac{2}{3})^{x}

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ 5=200(\frac{2}{3})^{x}

- Divide both sides by 200

∴ 0.025=(\frac{2}{3})^{x}

- Insert ㏒ for both sides

∴ log(0.025)=log(\frac{2}{3})^{x}

∴ log(0.025)=xlog(\frac{2}{3})

- Divide both sides by log(\frac{2}{3})

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly

8 0
3 years ago
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