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RUDIKE [14]
3 years ago
10

The area of a tiled kitchen floor is represented by the expression 4x2 + 24x + 27, where x represents the length of a single til

e. The length, l, of the floor is 9 feet more than twice the length of a tile, x. Which expression represents the width of the kitchen in terms of x?
Mathematics
2 answers:
Dafna11 [192]3 years ago
6 0

The correct answer should be "2x + 3".

Readme [11.4K]3 years ago
5 0
Let
x--------> <span>represents the length of a single tile
L-------> t</span><span>he length of the floor
W------> the</span><span> width of the floor
A--------> </span>area of a tiled kitchen floor
<span>
we know that
A=W*L
A=</span>4x²<span> + 24x + 27
</span>so
W*L=4x² + 24x + 27---------> equation 1
L=2x+9------> equation 2

substitute equation 2 in equation 1
W*[2x+9]=4x² + 24x + 27
W=[4x² + 24x + 27]/[2x+9]

therefore

the answer is
the <span>expression that represents the width of the kitchen in terms of x is
</span>W=[4x² + 24x + 27]/[2x+9]

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            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
3 years ago
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