The answers to each of the given problems are;
1) Sum of two smallest integers = 23
2) 3x + 6
3) 7.5 m/s²
<h3>How to find the sum of consecutive Integers?</h3>
1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;
x + (x + 1) + (x + 2) + (x + 3) + 20 = 70
4x + 26 = 70
4x = 70 - 26
4x = 44
x = 44/4
x = 11
Thus, sum of two smallest integers = 11 + 11 + 1 = 23
2) Let the consecutive odd numbers be;
x, (x + 2) and (x + 4)
Sum of these consecutive odd numbers is;
x + x + 2 + x + 4 = 3x + 6
3) We are given the equation to find the acceleration as;
(v_final)² - (v_initial)² = 2ad
We are given;
v_final = 40 m/s
v_initial = 10 m/s
d = 100 m
Thus;
40² - 10² = 2a(100)
1500 = 200a
a = 1500/200
a = 7.5 m/s²
Read more about sum of integers at; brainly.com/question/17695139
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Answer:
28
Step-by-step explanation:
g(10)=3n-2
10=n
3(10)-2
REMEMBER PEMDAS
Parentheses, Exponent, Multiplication, Division, Addition, and Subtraction.
3(10)=30
30-2=28
Hope this helps have a wonderful evening!
Answer:
the answer is 1 I guess
Step-by-step explanation:
2/5 - 3/5
2-3/5
1
Answer:
C. 1
Step-by-step explanation:
Looking to the Venn's diagram, we can realize that g(1) = 0
If g(1) = 0, you just need to put 0 in place of x in f(x), so we have:
f(0) = 3√0 + 1
f(0) = 3•0 + 1
f(0) = 1
