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Rudik [331]
3 years ago
7

If discriminant is zero, how many solutions do I have?

Mathematics
1 answer:
kap26 [50]3 years ago
3 0
You would have one repeating real solution.
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2/5 k - 3/5 + 1/10 k
liraira [26]

Answer:

Step-by-step explanation:

2/ 5 k− 3 /5 k+ 1 /10 k = 2 /5 k+ −3 /5 k+ 1 /10 k

Combine Like Terms:

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Marizza181 [45]
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