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bulgar [2K]
3 years ago
7

E. 2078-01-08

Mathematics
1 answer:
Mazyrski [523]3 years ago
4 0

Answer:

the full question isn't there. what do you need to find the number of??

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What's absolute value |-8|
maks197457 [2]
The absolute value of a number can never be negative. That's because it represents the distance of a number from zero on a number line. The number -8 is 8 digits to the left of zero on a number line. So, the absolute value of -8 would be 8 .

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
7 0
3 years ago
Read 2 more answers
Evan, Claire, Jaya and Tim are running a 3 km relay race. Evan ran 7/8 of a km,
Vanyuwa [196]

Answer:

11/24

Step-by-step explanation:

7/8 + 11/12 + 3/4 + x = 3 km

7*3/8*3 = 21 / 24

11*2 / 12 * 2 = 22 /24

3*6 / 4*6 = 18/24

21/24 + 22/24 + 18/24 + x = 3

61 / 24 +  x = 3

x = 72/24 - 61/24

x = 11 / 24

Tim has to run 11/24 of the race

7 0
3 years ago
Solve for x: 2(10-2x) = 4(3x + 1). Write your answer as a fraction.
qwelly [4]

Answer:

\boxed{x=1}

Step-by-step explanation:

2(10-2x) = 4(3x + 1)

\sf Expand \ brackets.

20 - 4x = 12x + 4

\sf Subtract \ 12x \ and \ 20 \ from \ both \ sides.

20 - 4x - 12x - 20 = 12x + 4 - 12x - 20

-16x = -16

\sf Divide \ both \ sides \ by \ -16.

\displaystyle \frac{-16x}{-16} =\frac{-16}{-16}

x=1

4 0
3 years ago
Read 2 more answers
A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr
SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

7 0
2 years ago
Please help this is timed! I’ll give brainliest.
lakkis [162]

Answer:

a. Function 1

b. Function 3

c. Function 2, Function 3 and Function 4

Step-by-step explanation:

✔️Function 1:

y-intercept = -3 (the point where the line cuts across the y-axis)

Slope, using the two points (0, -3) and (1, 2):

\frac{y_2 - y_1}{x_2 -x_1} = \frac{2 -(-3)}{1 - 0} = \frac{5}{1} = 5

Slope = 5

✔️Function 2:

y-intercept = -1 (the value of y when x = 0)

Slope, using the two points (0, -1) and (1, -4):

\frac{y_2 - y_1}{x_2 -x_1} = \frac{-4 -(-1)}{1 - 0} = \frac{-3}{1} = -3

Slope = -3

✔️Function 3: y = 2x + 5

y-intercept (b) = 5

Slope (m) = 2

✔️Function 4:

y-intercept = 2

Slope = -1

Thus, the following conclusions can be made:

a. The function's graph that is steepest is the function whose absolute value of its slope is greater. Therefore Function 1 is the steepest with slope of 5

b. Function 3 has a y-intercept of 5, which is the farthest from 0.

c. Function 2, Function 3, and Function 4 all have y-intercept that is greater than -2.

-1, 5, and 2 are all greater than -2.

4 0
3 years ago
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