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3 years ago

12

Bailey writes the expression g2 + 14g + 40 to represent the area of a planned school garden in square feet. If g = 5, what are t

he dimensions of the school garden?
20 feet by 2 feet
10 feet by 4 feet
12 feet by 7 feet
15 feet by 9 feet

1 answer:

stealth61 [152]3 years ago

6 0

I hope this helps you

g^2+14g+40

(g+4)(g+10)

g+4=9

g+10=15

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What expression represents the area???

galben [10]

Answer:

B.

Step-by-step explanation:

Area is width times height.

(5p-7)(3p+4)

Multiply using FOIL method

(First, outer, inner, last)

(5p*3p) + (5p*4) + (-7*3p) + (-7*4) =

15p² + 20p -21p - 28 =

15p²-p -28 =

B is the closest one. They might have made a typo.

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3 years ago

Help ASAP please and explain tooo

Alla [95]

Answer:

A not similar

Step-by-step explanation:

These triangles are not similar

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3 years ago

When two numbers have a sum equal to ___ the numbers are additive inverses example of __ + -9 =0 and 18 + __ = 0

Aliun [14]

Answer: Zero; 9; -18

Step-by-step explanation:

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5 0

3 years ago

You are driving home on a weekend from school at 55 mi/h for 110 miles. it then starts to snow and you slow to 35 mi/h. you arri

stepladder [879]

Okay lets get started.

I drove 110 miles with speed of 55 mi/hr so the time taken =

time = distance / speed

time = 110 / 55 = 2 hrs For the distance which is covered with 55 mi/hr speed.

Total time for reaching home is 4 hrs 15 minutes. (given in question)

Means rest distance after snow is covered in = 4 hrs 15 minutes - 2 hrs

= 2 hrs 15 minutes = 2 + 15/60 = 2.25 hrs

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So distance covered in snow driving is = 2.25 * 35 = 78.75 miles

Hence the total distance = 110 + 78.75 = 188.75 miles : Answer

Hope that will help :)

6 0

3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

4 years ago