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2 years ago

12

Does anyone know how to answer this question I'm having a lot of trouble with it?

1 answer:

Helen [10]2 years ago

5 0

Answer:

h = $\frac{2A}{(b+c)}$

Step-by-step explanation:

Formula for the area of a trapezoid is,

Area (A) = $\frac{1}{2}(b+c)h$

Here b and c are the bases and 'h' is the height of the trapezoid.

2A = $2[\frac{1}{2}(b+c)h]$

2A = (b + c)h

$\frac{2A}{(b+c)}=h$

Therefore, formula for the height of the trapezoid will be,

h = $\frac{2A}{(b+c)}$

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Please help. Thank you.

Trava [24]

Answer:

By the Pythagoras theorem, the hypotenuse (c), is equivalent to:

a^2+ b^2= c^2 where a and b are the other two sides of the right angled triangle, hence c= square root (15^2+ 20^2)= 25

4 0

2 years ago

Mang Nathaniel is selling two kinds of vinegar. Silver duck is priced at Php

Vladimir [108]

Answer:

Reyna Puti sold = 20 bottles

Step-by-step explanation:

Silver duck = Php 10 per bottle

Reyna Puti = Php 15 per bottle

Silver duck sold = 30 bottles

Reyna Puti sold = x bottles

Total sales = Php 600.00

Total = cost of Silver duck * number sold + cost of Reyna Puti * number sold

600 = 10 * 30 + 15 * x

600 = 300 + 15x

600 - 300 = 15x

300 = 15x

x = 300/15

x = 20 bottles

Reyna Puti sold = 20 bottles

3 0

2 years ago

Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru

jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time ( $t_{T}$ ) that Keenan will be from home is the sum of run ( $t_{R}$ ), hang out ( $t_{H}$ ) and walk times ( $t_{W}$ ), measured in hours:

$t_{T} = t_{R}+t_{H}+t_{W}$

If Keenan runs and walks at constant speed, then equation above can be expanded:

$t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}$

Where:

$x_{R}$ , $x_{W}$ - Run and walk distances, measured in miles.

$v_{R}$ , $v_{W}$ - Run and walk speeds, measured in miles per hour.

Given that $x_{R}=x_{W} = 2.5\,mi$ , $v_{R} = 6\,\frac{mi}{h}$ , $v_{W} = 4\,\frac{mi}{h}$ and $t_{H} = 0.75\,h$ , the total time is:

$t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }$

$t_{T} = 1.792\,h$ ( $1\,h\,48\,m$ )

Kennan will be from home approximately an hour and 48 minutes.

7 0

2 years ago

What is the answer to the question

fenix001 [56]

Answer:

Step-by-step explanation:

Sorry not sorry I really need the points

6 0

2 years ago

Read 2 more answers

7 students have 8 books each. Which helps you find the total number of books?

bija089 [108]

Answer:

7 × 8

Step-by-step explanation:

7 number of students × 8 books each student has 7 × 8 = 56

5 0

2 years ago