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LuckyWell [14K]

3 years ago

5

What plus 26 gives 66?

1 answer:

Diano4ka-milaya [45]3 years ago

8 0

sixty-six minus twenty-six is forty.

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Juliette is making a fruit salad.she purchased 9 2/3 ounces each of 6 different fruits . how many ounces of fruit did she purcha

Anettt [7]

9 2/3 total ounces is a total split up among 6 fruits.

So we need to divide 9 2/3 among the 6 fruits.

= 9 2/3 divide 6

= change 9 2 / 3 in improper fraction
= 9*3 + 2/3

= 29/3 divided by 6/1

= 29/3 x 1/6

= 29/18, change that to mixed fractions.

The answer is 1 11/18 ounces of each fruit.

3 0

3 years ago

Rewrite (123 + 456) + 789 using the Associative Law of Addition

adelina 88 [10]

Answer:

123 + (456 + 789)

Step-by-step explanation:

since this is an addition problem, the parenthesis don't matter, and they can be put wherever you want.

(123 + 456) + 789

123 + 456 + 789

(123 + 456 + 789)

123 + (456 + 789)

technically, any of these would work, but I think the kind of answer the problem is looking for is;

123 + (456 + 789)

5 0

3 years ago

Find the error in the problem.

Sonbull [250]

The 2nd step, you're supposed to combine like terms (20h and 2h) but not the 5 because it doesn't have a h next to it.

5 0

3 years ago

Read 2 more answers

Hector and his brother, Lee, collect toy cars. Hector has c cars, where c > 10. Lee has 35% more cars than Hector, but he don

son4ous [18]

Answer:

b) c + 0.35c − 10

Step-by-step explanation:

3 0

3 years ago

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

3 years ago