Using probability concepts, it is found that:
- The theoretical probability of spinning an odd number is equal to 3/5 = 0.6.
- The experimental probability of spinning an odd number is equal to 1/2 = 0.5.
- Therefore, the theoretical probability of spinning an odd number is greater than the experimental probability of spinning an odd number.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
A theoretical probability is calculated without considering experiments, and we have that 3 out of the 5 numbers(1,3,5) and are odd, hence the theoretical probability is given by:
pT = 3/5 = 0.6.
For an experimental probability, we consider the experiments. Of the 6 spins, 3 resulted in an odd number, hence the experimental probability is given by:
p = 3/6 = 1/2 = 0.5.
Therefore, the theoretical probability of spinning an odd number is greater than the experimental probability of spinning an odd number.
More can be learned about probabilities at brainly.com/question/14398287
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Step-by-step explanation:
5x+52=9x+20
subtract 5x on both sides
subtract 20 on both sides
32=4x
divide by 4 on both sides
x=8
plug in x to the equations for A, D, and C
A and D are 92°
C is 56°
B and C will add up to 90, so
90-56=34°
13y-6=34
add 6 on both sides
13y=40
divide by 13
y=40/13 (I don't wanna calculate that)
Answer:
Step-by-step explanation:
We are given the following function in the question:
We have to derivate the given function.
Formula:
The derivation takes place in the following manner
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
