Answer:
41.67% probability that a student has a dog given that they have a cat
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: having a cat.
Event B: having a dog.
12 of 27 students have a cat:
This means that 
5 students who have a cat and a dog.
This means that 
What is the probability that a student has a dog given that they have a cat?
41.67% probability that a student has a dog given that they have a cat
Answer:
Step-by-step explanation:
35
It's still 36% because you droppet it and then gain it back up
Answer: First option. y-15=5(x-3)
Solution:
We can take any pair of points of the table. For example:
P1=(3, 15)=(x1, y1)→x1=3, y1=15
P2=(5, 25)=(x2,y2)→x2=5, y2=25
And we can find the slope m using the following formula:
m=(y2-y1)/(x2-x1)
m=(25-15)/(5-3)
m=(10)/(2)
m=5
Now we can apply the point-slope formula to find the equation of the right line:
y-y1=m(x-x1)
Replacing y1=15, m=5, and x1=3
y-15=5(x-3)
The answer should be...
(6,0) !
All you have to do is count 6 spots to the right of the origin.
