X+3y=15 and 4x+2y=30

1 answer:

4 0

Subsitution
minus 3y from both sides in the first equatio
x=15-3y
subsitute 15-3y for x in other equation

4(15-3y)+2y=30
60-12y+2y=30
60-10y=30
minus 60 both sides
-10y=-30
divide both sides by -10
y=3

sub back

x=15-3y
x=15-3(3)
x=15-9
x=6

(x,y)
(6,3)

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