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nalin [4]
3 years ago
12

Which statements are true regarding the area of circles and sectors? Check all that apply.

Mathematics
2 answers:
charle [14.2K]3 years ago
7 0

Answer:

A, B, D, E

Step-by-step explanation:

Got it right on edge

Advocard [28]3 years ago
7 0

Answer:

A, B, D, E

Step-by-step explanation:

Got it correct.

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Reflect the figure over the line y-2.<br><br><br> Please help
Lana71 [14]
(5,0) (9,6) (7,7) (2,7)
8 0
2 years ago
Consider the data set
Serhud [2]
Answer: 3.496

Explanation: You find the mean, which is 57.714. Next, you subtract the mean from each number in the dataset, |55 - 57.714|, |59 - 57.714|, etc. You then add all of those numbers together and divide them by the amount of numbers like you would determining the mean. This gives you 3.496. Also sorry for taking so long to respond I’m on my phone and cannot type as fast as I would on pc.
7 0
1 year ago
I’m not sure why the picture didn’t work
lutik1710 [3]

Answer:

4.1

Step-by-step explanation:

6 0
2 years ago
Find ten rational numbers between -1 by 5 and 1 by 2 ​
uysha [10]

Answer:

Step-by-step explanation:

First both the rational numbers should have same denominators. So, find least common denominator

Least common denominator is 10

\frac{-1}{5}=\frac{-1*2}{5*2}=\frac{-2}{10}\\\\\\\frac{1}{2}=\frac{1*5}{2*5}=\frac{5}{10}\\\\\\

Now multiply  the numerator  and denominators of the both the numbers by 10.

\frac{-2*10}{10*10}= \frac{-20}{100} \ and \ \frac{5*10}{10*10}=\frac{50}{100}\\\\\\Now\ 10 \ rational  \ numbers \ between\frac{-20}{10} \ and \ \frac{50}{100} \ is \\\\\\\frac{-19}{100},\frac{-18}{100},\frac{-17}{100},\frac{-16}{100}.\frac{-15}{100},\frac{-14}{100},\frac{-13}{100},\frac{-12}{100},\frac{-11}{100};\frac{-10}{100}

8 0
2 years ago
Let A and B be two disjoint events such that P(A) = .30 and P(B) = .60. What is P(A and B)? 0.18 0.72 0.90 0 none of the above
antiseptic1488 [7]

Answer:

0

Step-by-step explanation:

If two events are disjoing (aka mutually exclusive) that means that there is 0 overlap or the intersection equals 0

So the probability of A <em>and </em>B occuring is 0 (because P(A∩B)= 0)

4 0
2 years ago
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