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murzikaleks [220]
3 years ago
5

During what step of the Communication Process Model does the receiver's motivation and ability to remember to act on a message b

ecome most important?
A. When selecting the message
B. When providing feedback
C. When receiving the message
D. When responding to the message
E. When decoding the message
Computers and Technology
2 answers:
emmasim [6.3K]3 years ago
7 0

Answer:

A

Explanation:

because the receiver remember information

levacccp [35]3 years ago
4 0

Answer:

D. When responding to the message

Explanation:

As we know that

The communication process is of  steps i.e

From sender to receiver i.e

Sender, encoding of message, channel, decoding the message, and the receiver

The sender to receiver and received to sender is link through a feedback

The sender is the person who send the message, the message is converted i.e to be called as encoding of message. The channel is a medium through which this process connected to each other and the receiver converted the message sent by the sender i.e decoding, and the receiver is the person who received the message

So in order to motivated the receiver and act on a message the message respond reflects the given situation as it enables to remember the message.

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Write a zip code class that encodes and decodes 5-digit bar codes used by the U.S. Postal Service on envelopes. The class should
8_murik_8 [283]

Answer:

#include<iostream>

#include<string>

using namespace std;

class zip_code

{

private:

int zipcode;

string get_string(int num)

{

string str="";

if(num == 0) return "11000";

if(num>7)

{

str.append("1");

num = num-7;

}

else

str.append("0");

if(num>4)

{

str.append("1");

num = num-4;

}

else

str.append("0");

if(num>2)

{

str.append("1");

num = num-2;

}

else

str.append("0");

if(num>1)

{

str.append("1");

num = num-1;

}

else

str.append("0");

str.append("0");

return str;

}

public:

zip_code(int barcode)

{

if(barcode<10000 || barcode>99999)

cout <<"Invalid Bar code passed to constructor." << endl;

else

zipcode = barcode;

}

zip_code(string barcode)

{

if(barcode.length()>27)

cout <<"Invalid Bar code passed to constructor." << endl;

else

{

int zipper = 0;

string str_local = barcode.substr(1,barcode.length()-2);

for(int i=0; i<str_local.length()-5; i+=5)

{

int local = 0;

local = 7*(str_local[i]-'0') +

       4*(str_local[i+1]-'0') +

       2*(str_local[i+2]-'0') +

       1*(str_local[i+3]-'0');

if(local == 11) local = 0;

       zipper = zipper*10 + local;

}

zipcode = zipper;

}

}

string getZipcode()

{

string str = "1";

int first = zipcode/10000;

int second = (zipcode - first*10000)/1000;

int third = (zipcode - first*10000-second*1000)/100;

int fourth = (zipcode - first*10000-second*1000-third*100)/10;

int fifith = (zipcode - first*10000-second*1000-third*100-fourth*10);

str.append(get_string(first));

str.append(get_string(second));

str.append(get_string(third));

str.append(get_string(fourth));

str.append(get_string(fifith));

str.append("1");

return str;

}

int get_zipCode()

{

return zipcode;

}

};

int main()

{

zip_code z1(123456);

zip_code z2(99504);

cout << z2.getZipcode() << endl;

system("pause");

return 0;

}

4 0
4 years ago
What is (12.2a + 9.7b) – (18.1b – 0.2a) – (6.7a + 6.8b), simplified?
Inga [223]
The answer should be 5.7a - 15.2b
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cupoosta [38]
Because electricity powers everything , electricity can do anything
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Assume x represents an integer number, what is the highest index value in the following array? byte[] values = new byte[x]; Grou
scoundrel [369]

Answer:

You forgot to add a group of choices, however assuming this programming language uses 0-based indexes the answer would be x - 1

Explanation:

Zero based index languages have array indexes starting at 0. When you create that array, you use x to define the amount of elements, however due to the array starting at the index 0, the arrays highest index would be x - 1 instead of x.

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