It seems like a great county to visit, with many great views and tourist spots throughout.
I believe the answer is A. because he has to listen to what the people tell him and he information he has to think about and make a choice on what to reply with.
I hope this helps and its correct please let me know if its wrong have a great day//night.
Spatial representation allows information to be viewed at a glance without needing to address the individual elements of the information separately or analytically.
<h3>What do you mean information?</h3>
- Information is a stimulus with meaning for the receiver in a specific situation.
- Data is a broad term that refers to information that is entered into and stored in a computer.
- Data that has been processed, such as formatting and printing, can be interpreted as information again.
- When you communicate verbally, nonverbally, graphically, or in writing, you are passing on knowledge gained through research, instruction, investigation, or reading the news.
- Information is known by many different names, including intelligence, message, data, signal, and fact.
- Information helps to avoid study duplication. Information stimulates the cognitive processes of users, particularly scholars.
- Scientists, engineers, academics, and others benefit from the use of information.
To learn more about Information, refer to:
brainly.com/question/4231278
#SPJ4
Explanation:
Explanation:
RSA encryption is performed by calculating C=M^e(mod n).
However, if n is much larger than e (as is the case here), and if the message is not too long (i.e. small M), then M^e(mod n) == M^e and therefore M can be found by calculating the e-th root of C.
Answer:
class studentType: public personType
{
public:
virtual void print() = 0;
virtual void calculateGPA() = 0;
void setID(long id) {
studentId = id;
}
void setCourses(const string c[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
courses[i] = c[i];
}
}
void setGrades(const char cG[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
coursesGrade[i] = cG[i];
}
}
long getID() {
return studentId;
}
string* getCourses() {
return courses;
}
char* getGrades() {
return coursesGrade;
}
studentType(string fName = "", string lastName = "",
long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);
private:
long studentId;
string courses[6];
char coursesGrade[6];
int noOfCourses;
};
Explanation:
Code rewritten