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Neporo4naja [7]
3 years ago
9

Find the Sin, Cos, and Tan of the following angle:

Mathematics
1 answer:
aksik [14]3 years ago
5 0

$\sin 45^\circ=\frac{-1}{\sqrt{2} },  \ \cos45^\circ=\frac{1}{\sqrt{2} }, \ \ \tan 45^\circ=-1

Solution:

In the given right triangle,

θ = 45°

Opposite side to θ = –1

Adjacent side to θ = 1

Hypotenuse = \sqrt{2}

Using basic trigonometric ratio formulas,

$\sin \theta=\frac{\text { Opposite }}{\text { Hypotenuse }}

$\sin 45^\circ=\frac{-1}{\sqrt{2} }

$\cos \theta=\frac{\text { Adjacent }}{\text { Hypotenuse }}

$\cos45^\circ=\frac{1}{\sqrt{2} }

$\tan \theta=\frac{\text { Opposite }}{\text { Adjacent }}

$\tan 45^\circ=\frac{-1}{1}=-1

Therefore,

$\sin 45^\circ=\frac{-1}{\sqrt{2} },  \ \cos45^\circ=\frac{1}{\sqrt{2} }, \ \ \tan 45^\circ=-1

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