(07.02 LC) What is the greatest common factor of x^8 and x^5?

Mathematics

1 answer:

nydimaria [60]3 years ago

8 0

Answer:x

Step-by-step explanation:

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In a quadrilateral MNOP the length of side MN is (4x − 7) units and the length of side ON is (7 − 3x) units. What value of x wil

artcher [175]

In a rhombus, all sides are equal.

So for the quadrilateral MNOP to be a rhombus, the given sides have to be equal. THat is

$MN=ON$

$4x-7 =7-3x$

Adding 3x to both sides and addinf 7 to both sides

$7x = 14$

Now we need to get rid of 7 and for that we do division, that is

$\frac{7x}{7} = \frac{14}{7}$

$x=2$

Correct option is the second option .

6 0

3 years ago

A rectangle has a length of 45 inches less than 4 times its width. if the area of the rectangle is 3325 square inches, find the

Maru [420]

The length of the rectangle is based on its width, so let's call width w and put the length in terms of the width. We are told that the width is 45 less than 4 times the width, so the length is 4w - 45. Area is found by multiplying length times width and we are given the area as 3325. So we will set up length times width and solve for w, which we will then use to solve for l. 3325 = (4w - 45)(w). Multiplying out we have $3325=4w^2-45w$ . Move the constant over by subtraction and then we will have a quadratic that can be factored to solve for w. $4w^2-45w-3325=0$ . We would put that through the quadratic formula to solve for w. When we do that we get that w = 35 and w = -23.75. The 2 things in math that will never EVER be negative is time and distance/length, so -23.75 is out. That means that the width is 35. The length is 4(35) - 45 which is 95. The dimensions of your rectangle are length is 95 and width is 35. There you go!