Answer:
Figure of the function is included below as attachment.
Step-by-step explanation:
Let As first step we have to find x intercepts, maxima and minima from 0 to 2π, which are needed to plot given function. Cosine is a trigonometric function bounded between -1 and 1 with a periodicity of 2π.
x-Intercepts
x-intercepts are those points of the function such that . That is:
In this case, there is a periodicity of π for . The x-intercepts are in the following set:
Maxima
Maxima are those points of the function such that . That is:
In this case, there is a periodicity of 2π for . Maxima are in the following set:
Minima
Minima are those points of the function such that . That is:
In this case, there is a periodicity of 2π for . Minima are in the following set:
Lastly, we proceed to plot the function as well as its x-intercepts, maxima and minima with the help of a plotting tool.
Answer: choice B) 36 degrees
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Work Shown:
Use the law of cosines
c^2 = a^2 + b^2 - 2*a*b*cos(C)
(DF)^2 = (EF)^2 + (DE)^2 - 2*(EF)*(DE)*cos(E)
6^2 = 10^2 + 7^2 - 2*10*7*cos(E)
36 = 100 + 49 - 140*cos(E)
36 = 149 - 140*cos(E)
36 - 149 = -140*cos(E)
-113 = -140*cos(E)
cos(E) = -113/(-140)
cos(E) = 0.80714285714286
E = arccos(0.80714285714286)
E = 36.1822872211523 <<--- see note below
E = 36 degrees
Note: arccos is the arccosine function, or the inverse cosine function. Make sure you are in degree mode
If the last one is supposed to be 7(8+3), it would be equivalent to 56+21
It is given that the measurement of arc AC = 155 . And AB is the diameter, so measurement of arc AB=180 degree . Therefore arc BC = arc AB - arc AC = 180-155=25 . And the radius divides chord CD in two equal parts, so it divides the arc too in two equal parts. Therefore if the measurement of arc CB =25 , then the measurement of arc BD =25 too. Hence x =25 .
Working be x and classes be y
So
And
Graph both .
The solution region is the best way.(Blue part)