Answer:
Just substitute 0 instead of f (x),therefore
The answer option is C
Answer:
12
+ 29x - 14
Step-by-step explanation:
(3x+2)(4x-7)
Multiply out 3x first then 2
(3x * 4x) - (3x * -7) + (2 * 4x) + (2 * -7)
12 - (- 21x) + 8x + ( -14)
12 + 21x + 8x - 14 Combine like terms
12 + 29x - 14
Answer:
The slope intercept form is y=1/6x+1
Step-by-step explanation:
Answer:
A. 9x^4 and 3x^5y
Step-by-step explanation:
there are two ways to solve this:
first way:
You can solve this my substituting numbers for x and y in this case i used 2 for x and 3 for y and see which one is equal to the original equations
the second way is the regular way
when you add or subtract numbers with variables and exponents you want to add the constants and add the exponents in this case 
is the same as 
= 
and you can do the same process for subtraction
= 
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
