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Serggg [28]
3 years ago
14

Find the length and the midpoind of the segment with the given endpointsA(2,3 )and B(5,7)

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

Suppose,~a~line~segment~has~midpoints~(x_1,y_1)~and~(x_2,y_2). Then,\\Midpoint~of~the~line = (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})\\Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\According~ to~ the ~question,\\(x_1,y_1) = A(2,3)\\(x_2,y_2) = B(5,7)\\Midpoint~of~AB = (\frac{2+5}{2},\frac{3+7}{2}) = (\frac{7}{2},5)\\AB = \sqrt{(5-2)^2+(7-3)^2} = \sqrt{3^2+4^2} = 5units

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i am measurng two line segments the first line is 30centi meter long the second line segment is 500milli meter how long are the
Alexeev081 [22]

Answer    

Find out the how long are the two line segments together answer in cm .

To prove

As given

i am measurng two line segments the first line is 30centimeter long.

The second line segment is 500 millimeter .

As

1 millimeter = 0.1 centimeter

Now convert  500 millimeter into centimeter .

500 millimeter = 500 × 0.1 centimeter

                         = 50 centimeter

Thus second line segment be  50 centimeter long .

Total length of  two line segments = 30 + 50

                                                        = 80 cm

Therefore the 80 cm long are the two line segments together answer in cm .




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Subtract.<br> (-9r - 3) - (7r - 1)<br> Submit
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Answer:

-16r -2

Step-by-step explanation:

plz brainliest :)

do you want an explanation?

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