Answer:
=94.985m²
Step-by-step explanation:
Area = πr²
π=3.14
r=5.5
-
Find the radius,
11/2=r
r=5.5
-
Area=
3.14x 5.5x 5.5
3.14x30.25
=94.985m²
Answer:
GURL MY MATH TEACHER GAVE ME THE SAME SHEET A MONTH AGOO
YASS
1.) x is less than or equal to 3
2.) x greater than or equal to 2
3.) x < -1
4.) x greater than or equal to 3
5.) x>2
6.) x greater than or equal to 1
Answer:
NO
Step-by-step explanation:
To find out which observation to classify as an outlier, whether the largest or not, a very good approach or way to do this is to apply the 1.5(IQR) rule.
According to the rule, for finding the largest observation in the data that can be classified as an outlier, we would use the formula = Q3 + 1.5(IQR).
Q3 = 120
IQR = Q3 - Q1 = 120 - 95 = 25
Lets's plug these values into Q3 + 1.5(IQR)
We have,
120 + 1.5(25)
= 157.5
Since our max in the observation is given as 155, the largest observation in the data set cannot be set as an outlier because 157.5 which we got from our calculation is higher than the max value we have in the data set.
Our answer is NO.
However, the smallest observation should be set as outlier because:
Q1 - 1.5(IQR) = 95 - (1.5*25) = 57.5, which gives us an outlier that falls within our data range.
On the map, a distance of 20 miles are represented by 1 inch .
So distance of 1 mile is represented by
And therefore, distance of 135 miles are represented by
