X=- 8x=4 x=2+5i
(x+8)(x-4)(x-(2+sqrt(-25))
x^2+4x-32(x-2+sqrt(-25))
x^3+4x^2-32x-2x^2+8x-64+x^2(5i)+4x5i-32(5i)
now simplify
5 tens because 6 tens plus 5 ones is equal to 65 and x tens plus 15 ones is equal to 65 also so it would be 5 tens because 5 times 10 equals 50 then plus 15 equals 65 so 65=65
Answer: 5 tens
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Answer:
x(t) = -1 + 4t
y (t) = 3 - 5t
Step-by-step explanation:
The end points of the line segment are (-1, 3) and (3, -2).
Let a = (-1,3) and b = (3,-2)
Now, find the value of (b-a)
(b-a) = ((3+1), (-2-3))
b-a = (4, -5)
Therefore, the parametrization of the given line segment is
r(t) = a + (b-a)t
r(t) = (-1,3) +(4,-5)t
r(t) = (-1+4t, 3-5t)
We can rewrite this as
x(t) = -1 + 4t
y (t) = 3 - 5t
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The coefficient is the number before the x
In this case, it is 3
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Answer:
Step-by-step explanation:
3 3/4 ÷ 7/12
= 15/4 ÷ 7/12
= 15/4 x 12/7
= 6 3/7 rounds <=== so 6 complete rounds