The equation stems from the principle concept of Hooke's Law. After derivation, the general equation for finding the work of a stretch spring is written below:
W = k[(x₂ - x₁) + (x₁ - xn)]
where
k is the spring constant
xn is the natural length of the spring
x₁ is the length after stretching
x₂ is the length after stretching even further
Suppose the spring was only stretched once, then x₁ = x₂. The equation is simplified to:
<em>W = k(x₁ - xn)</em>
Answer:
Let m∠BCE = x
Then m∠ACE = x as well since CE is bisecting ∠ACB.
- m∠ACD + x + x = 180° ⇒
- m∠ACD = 180° - 2x
Consider ΔBEC
<u>Since BE = EC, the opposite angles are congruent:</u>
<u>Then:</u>
<u>Find the angle BEC:</u>
- m∠BEC = 180° - (x + x) = 180° - 2x
<u>Comparing the above we see that:</u>
Answer:
x^b=x^3
Step-by-step explanation:
(ax^2)(-6x^b)=12x^5
(a)(6)=6a or a6
(x^2)(x^b)=x^5
x^3 because
(a^b)(a^c)=a^b+c
Hope this helped.
Answer: what do you mean ?
Step-by-step explanation:
Answer: 5 ft
Step-by-step explanation:
Area of a rectangle (which is the shape of a regular flag) = L* W.
W = Area/L = 9.5/1.9 = 5ft.