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Alexxx [7]
3 years ago
10

HELP!!!!!!!!! I DONT UNDERSTAND THIS

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0

Answer:

x=86^{\circ}

y=94^{\circ}

z=54^{\circ}

Step-by-step explanation:

First, let's look at the largest triangle (two smaller triangles are combined) to solve for z. Since the sum of the angles in a triangle adds up to 180^{\circ}, we can write the equation:

20+74+32+z=180

z=180-126

z=54^{\circ}

Looking at the smaller triangle on the left, y (exterior angle) is the sum of the two opposite interior angles of the triangle on the left:

y=74+20

=94^{\circ}

Since x is the exterior angle of the triangle on the right, it is equivalent to the sum of the opposite interior angles of that triangle:

x=32+z

=32+54

=86^{\circ}

Hope this helps :)

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Step-by-step explanation:

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There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

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Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

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6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

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which is false, hence no solution exists



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