Actually, when you know 2 sides and an included angle, you use the Law of Cosines. (and we don't know if theta is an included angle).
Solving for side c
c^2 = a^2 + b^2 -2ab * cos(C)
c^2 = 36 + 16 - 2*6*4 * cos(60)
c^2 = 52 -48*.5
c^2 = 28
c = 5.2915

Using the Law of Sines
side c / sin(C) = side b / sin (B)
5.2915 / sin(60) = 4 / sin (B)
sin(B) = sin(60) * 4 / 5.2915
sin(B) = 0.86603 * 4 / 5.2915
sin(B) = 3.46412 / 5.2915
 sin(B) = 0.6546571451 
Angle B = 40.894 Degrees

sin (A) / side a = sin (B) / side b
sin (A) = 6 * sin (40.894) / 4
sin (A) = 6 * 0.65466 / 4
sin (A) = .98199
angle A = 79.109 Degrees

angle C = 60 Degrees

7 0

4 years ago

11. Marty has 1 dozen eggs. He needs 4 eggs

uysha [10]

Answer:

3 cakes can be baked with a dozen of eggs.

Step-by-step explanation:

1 dozen = 12

4 divided by 12 gives you 3.

3 0

3 years ago

Read 2 more answers

Hey square patio has an area of 212 ft.² how long is each side of the patio near of 0.05

Oksi-84 [34.3K]

The answer is 44944 i dont know just a guess

7 0

3 years ago

Read 2 more answers

The Skittles jar has a radius of 3.5 cm and a height of 11.5 cm. Using the two given boxes for reference what would be a good es

nevsk [136]

Answer:

1052

Step-by-step explanation:

The two given boxes for reference are presented below.

Since we know the dimensions of the first container, we can calculate its volume.

$V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3$

The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.

$v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3$

The second container held 258 skittles.

The volume of the second box is:

$V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3$

Using this facts, the volume of a single skittle would be

$v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3$

Therefore, the volume of single skittle is around to 0.42 cm³.

A skittle jar is a cylinder. Its volume is calculated by the formula

$V = r^2h \pi$ ,

where $r$ is the radius and $h$ is the height. From the given data, we have $r = 3.15 \text{cm}$ and $h = 11.5 \text{cm}$ . Hence, the volume of the jar is

$V = 3.5^2 \cdot 11.5 \cdot 3.14 = 442 \text{cm}^3$

Now, we can determine the number of skittles in the jar. Let $n$ be the number of skittles in the jar. Then,

$n = \frac{\text{volume of the jar}}{\text{volume of a skittle}} = \frac{V}{v} = \frac{442}{0.42} = 1052.38 \approx 1052\\$

4 0

3 years ago