A. The first-period class had a higher median score than the second-period class.
B.The second-period class scores had a higher mean than the first-period class scores.
C.The first-period class scores had a greater range than the second-period
class scores.
D.The second-period class scores had a greater mean absolute deviation than the first-period class scores.
Answer : B. .The second-period class scores had a higher mean than the first-period class scores.
The score diagram is attached below
From the diagram we can see that the score in first period is more than the score in second period. Most of the score are greater in second period.
So ,The second-period class scores had a higher mean than the first-period class scores.
Answer:
5 parts are shaded and 4 parts are white so:
There are 9 parts all together.
We can then form ratio's of the white areas and the shaded areas:
White Area Ratio =
Shaded Area Ratio =
Let the area of sqaure be equated to x, which means let the entire area of the square equal to x:
x = Area of whole square
Now we can form an equation :
So now we just need to solve for x:
The area of the square is:
Answer:
(1/2,-5/2)
Step-by-step explanation: