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3 years ago

An equivalent expression for (m1/3)1/5

Mathematics

2 answers:

KengaRu [80]3 years ago

8 0

1/15m is the answer. I think.

iris [78.8K]3 years ago

8 0

M/15

i think that may be the answer??

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PLEASE HELP RN! 50 POINTS IF YOU ANSWER THIS IS DUE TODAY

Alik [6]

Answer:

I graphed this...

Step-by-step explanation:

It is not linear because it is not a strait line and it doesnt go through the middle!

Hope this helps! :)

8 0

3 years ago

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

4 years ago

Pls help on both of these

Makovka662 [10]

Answer:

power of products

Step-by-step explanation:

just multiplied the powers

6 0

3 years ago

Solve for the variable C F=9/5c+32;C show steps

andrew11 [14]

F = 9/5c + 32
F - 32 = 9/5c
5/9(F - 32) = c

7 0

3 years ago

A dinner platter is in the shape of a regular decagon. The platter has an area of 161 square inches and a side length of 4.6 inc

REY [17]

When I saw this, I said to myself "Self ! We don't know anything about
decagons.", and then I went searching online for stuff about decagons.
This just goes to show how stupid I can be when I don't take a little time
to THINK before I go running around screaming.

-- When you draw all the lines from the center to the vertices of the
decagon, you'll have 10 little triangles.

-- The area of the whole thing is 161 square inches, so the area of each
little triangle is 1/10 of that . . . . . 16.1 square inches.

-- The area of each little triangle is (1/2) (base) (height), just like
every other triangle.
The base is the 4.6 inches of one side of the decagon.

 Area = (1/2) (base) (height)

Multiply each side by 2: 2 x area = (base) x (height)

Divide each side by (base): (2 x area) / (base) = height

Height = (2 x 16.1) / (4.6) = 7 inches .

Let that be a lesson to both of us.
THINK before you jump.

6 0

4 years ago