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lana66690 [7]
3 years ago
12

PLEASE HELP!!! What is the distance, in units, between P=(−6,8) and Q=(9,8)?

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

15

Step-by-step explanation:

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Q)Use RLE to compress the following data in the image
kari74 [83]

Answer:

tfrrbtrgt

Step-by-step explanation:

8 0
3 years ago
Please help i need this done QUICK im timed ill give the best answer brainliest
seraphim [82]

Answer:

x=−32/5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/2(1/4x−3/5)=1/4(2/5+3/4x)

(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)

1/8x+−3/10=1/10+3/16x

1/8x+−3/10=3/16x+1/10

Step 2: Subtract 3/16x from both sides.

1/8x+−3/10−3/16x=3/16x+1/10−3/16x

−1/16x+−3/10=1/10

Step 3: Add 3/10 to both sides.

−1/16x+−3/10+3/10=1/10+3/10

−1/16x=2/5

Step 4: Multiply both sides by 16/(-1).

(16/−1)*(−1/16x)=(16/−1)*(2/5)

x=−3/25

7 0
3 years ago
What is 0.000001 written as a power of ten?
AleksandrR [38]
a^{-n}=\dfrac{1}{a^n}\\\\10^{-n}=\dfrac{1}{10^n}=0.\underbrace{000...1}_{n}\\\\\text{examples:}\\\\10^{-2}=\dfrac{1}{10^2}=\dfrac{1}{100}=0.\underbrace{01}_{2} \\10^{-4}=\dfrac{1}{10^4}=\dfrac{1}{10,000}=0.\underbrace{0001}_{4}\\\\\text{therefore}\\\\0.\underbrace{000001}_{6}=10^{-6}\\\\\text{Answer:}\ \boxed{B.\ 10^{-6}}
7 0
3 years ago
Can yall help me with this pls its due rn and im cryinggggg ill definetly give brainliesttt : (
ivolga24 [154]

Answer:

In the first box, put 24y

In the second box, put 16

Step-by-step explanation:

3y x 8 = 25y

8 x 2 = 16

<em>Hope that helps! :)</em>

<em></em>

<3 Cin

6 0
3 years ago
Read 2 more answers
Use an induction proof to prove this statement:<br> For n≥1, 4^n+5 is divisible by 3.
Tpy6a [65]

Answer:

See below

Step-by-step explanation:

We shall prove that for all n\in\mathbb{N},3|(4^n+5). This tells us that 3 divides 4^n+5 with a remainder of zero.

If we let n=1, then we have 4^{1}+5=9, and evidently, 9|3.

Assume that 4^n+5 is divisible by 3 for n=k, k\in\mathbb{N}. Then, by this assumption, 3|(4^n+5)\Rightarrow4^k+5=3m,\: m\in\mathbb{Z}.

Now, let n=k+1. Then:

4^{k+1}+5=4^k\cdot4+5\\=4^k(3+1)+5\\=3\cdot4^k+4^k+5\\=3\cdot4^k+3m\\=3(4^k+m)

Since 3|(4^k+m), we may conclude, by the axiom of induction, that the property holds for all n\in\mathbb{N}.

3 0
2 years ago
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