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Ronch [10]
3 years ago
5

ASAP : Hilda looks at a CD and sees different colors. Which best explains why she sees different colors when light strikes a CD?

Physics
2 answers:
miv72 [106K]3 years ago
8 0
<h3><u>Answer;</u></h3>

Different wavelengths of light bend at different angles.

<h3><u>Explanation</u>;</h3>
  • When light hits an object, some of the light waves are reflected off the object and some are absorbed. For example, if an individual is looking at a red apple, red light waves are reflected off the apple and all the rest of the color are absorbed. Similarly when the individual is looking at a lemon, yellow light waves are reflected and all the other colors are absorbed.
  • <em><u>Different wavelengths of light bend at different angles which explains the dispersion of light to generate different colors. Therefore, when the light ray hits the CD, different wavelengths of light bends at different angles and the light gets separated into different bands of light. This explains the reason why Hilda saw different colors.</u></em>
m_a_m_a [10]3 years ago
7 0
The appropriate answer is ' The smooth surface of the CD causes wavelengths of light to scatter. The CD at this point acts somewhat like a prism splitting white light into the colors of the rainbow. This is called the visible spectrum of light and is composed of the colors red, orange, yellow, green, blue, indigo and violet. 
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You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
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<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

Hence, the Young's modulus for the wire is 6.378\times 10^{10}N/m^2

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