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andrew11 [14]
3 years ago
10

A displacement is related to time as x = A sin(2?ft), where A and f are constants. Find the dimensions of A. [Hint: A trigonomet

ric function appearing in an equation must be dimensionless.]
A. L * T
B. L / T
C. L
D. T / L
E. T
Physics
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

The right option is C. i.e L

Explanation:

Dimension of a quantity is the collection of the indexes of each of the fundamental quantities contained in it.

Therefore, to get the dimension of A in the equation

X=Asin(2(pi)ft)

Making A the subject of the formula

A = X / (sin(2(pi)ft)

Since sin(2(pi)ft which is a trigonometric function does not have a dimension

A = L

The dimension of A is L

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Answer:

35.3 N

Explanation:

U = 0, V = 0.61 m/s, s = 0.39 m

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Use third equation of motion

V^2 = u^2 + 2 as

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a = 0.477 m/s^2

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a boy looks at the reflection of his digital watch in a plane mirror and thinks the time is 10:11. what is the correct time?
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A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4
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Momentum before (p=mu)
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Which situation describes a system with decreasing gravitational potential energy?
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During your summer internship for an aerospace company, you are asked to design a small research rocket. The rocket is to be lau
Viktor [21]

Answer:

6.75 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration = 16 m/s²

g = Acceleration due to gravity = 9.81 m/s²

Let y be the distance the rocket is accelerating

960-y is the distance traveled in free fall

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 16\times y+0^2}\\\Rightarrow v^2=32y\ m/s

In free fall

v^2-u^2=2g(960-y)\\\Rightarrow 0-32y=2g(960-y)\\\Rightarrow -32y=2\times -9.81(960-y)\\\Rightarrow 960-y=\dfrac{-32}{2\times -9.81}y\\\Rightarrow 960-y=1.63098878695y\\\Rightarrow 960=2.63098878695y\\\Rightarrow y=\dfrac{960}{2.63098878695}\\\Rightarrow y=364.881828749\ m

The distance the rocket will keep accelerating is 364.881828749 m

After which it will travel 960-364.881828749 = 595.118171251 m in free fall

s=ut+\frac{1}{2}at^2\\\Rightarrow 364.881828749=0t+\frac{1}{2}\times 16\times t^2\\\Rightarrow t=\sqrt{\frac{364.881828749\times 2}{16}}\\\Rightarrow t=6.75353452598\ s

The time the rocket is accelerating is 6.75 seconds

5 0
3 years ago
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