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34kurt
3 years ago
10

*18 POINTS* Urgent!! Please answer

Mathematics
2 answers:
Sedaia [141]3 years ago
7 0

idk sorryyyyy but maybe try looking up formulas for the problem

Ksivusya [100]3 years ago
4 0
Total surface area = 2 * circular base + circumference * height
  =  2 * pi*(4)^2 +  8pi * 12
  =  32pi + 96pi
   = 128pi answer
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Write these numbers in order starting with the smallest 2.303,2.3,2.33,2.03
zavuch27 [327]
2.03, 2.3, 2.303, 2.33

3 0
3 years ago
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An ant is moving around the unit circle in the plane so that its location is given by the parametric equations (cos(Ď€ t), sin(Ď
adelina 88 [10]

Answer:

yes


Step-by-step explanation:


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If 1 serving is equal to 3/4 cup, how many cups does it take to get 19.5 grams of protein?
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Answer: 26

Step-by-step explanation:

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3 years ago
Find the slope and y-intercept of the line that is parallel to y = -x - 3 and passes through the point (3, -2)
motikmotik
Use point slope formula y-y1=m(x-x1)
You are told that y=-x+3. This equation is of the form y=mx+b. Where m=-1. m is the slope. And you have a point (x1,y1) that is (3,-2). With all of this in mind, you then plug all of these details into the point slope formula y-y1=m(x-x1)

In point slope form, you have the following:


y-(-2)=-1(x-3).

To turn this into slope intercept form, simplify y-(-2) to get y+2 and distribute in the -1 to get:

y+2=-x+3

Subtract 2 from both sides to get

y=-x+1

In slope intercept form, the answer is
y=-x+1 and in point slope form, the answer is y+2=-x+3

Hope this helps!!!

3 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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